Aidez moi à résoudre entièrement l'exercice 2, il me faut les calculs expliqués svp.

A=7/5-7/3*15/14=7/5-105/42=294/210-525/210=-231/210=-11/10
B=8/5-3/4:9/8=8/5-3/4*8/9=8/5-24/36=24/15-10/15=14/15
C=[tex] \frac{ \frac{8}{3}- \frac{2}{5} }{ \frac{7}{5} } =[/tex](8/3-2/5)5/7=(40/15-6/15)5/7=36/15*5/7=180/105=12/7

bonsoir

a = 7/5  - 105/42
a = 7/5 - 5/2
a = 14/10 - 25/10
a = - 11/10

b = 8/5 - 3/4 x 8/9
b = 8/5 - 24/36
b = 8/5- 2/3
b = 24/15 - 10/15
b = 14/15

c= (8/3 - 2/5) : 7/5
c = ( 40/15 - 6/15) : 7/5
c = 34/15 x 5/7
c = 170/105
c = 34/21